1-2cos^2(x)=sin(Pi-x)

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Solution for 1-2cos^2(x)=sin(Pi-x) equation:


Simplifying
1 + -2cos2(x) = sin(Pi + -1x)

Multiply cos2 * x
1 + -2cos2x = sin(Pi + -1x)
1 + -2cos2x = (iP * ins + -1x * ins)

Reorder the terms:
1 + -2cos2x = (-1insx + i2nsP)
1 + -2cos2x = (-1insx + i2nsP)

Solving
1 + -2cos2x = -1insx + i2nsP

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2cos2x = -1insx + -1 + i2nsP

Combine like terms: 1 + -1 = 0
0 + -2cos2x = -1insx + -1 + i2nsP
-2cos2x = -1insx + -1 + i2nsP

Reorder the terms:
-2cos2x = -1 + -1insx + i2nsP

Divide each side by '-2os2x'.
c = 0.5o-1s-2x-1 + 0.5ino-1s-1 + -0.5i2no-1s-1x-1P

Simplifying
c = 0.5o-1s-2x-1 + 0.5ino-1s-1 + -0.5i2no-1s-1x-1P

Reorder the terms:
c = 0.5ino-1s-1 + -0.5i2no-1s-1x-1P + 0.5o-1s-2x-1

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